Integrand size = 21, antiderivative size = 59 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\left (a^2+b^2\right ) \log (a+b \tan (c+d x))}{b^3 d}-\frac {a \tan (c+d x)}{b^2 d}+\frac {\tan ^2(c+d x)}{2 b d} \]
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Time = 0.09 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {3587, 711} \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\left (a^2+b^2\right ) \log (a+b \tan (c+d x))}{b^3 d}-\frac {a \tan (c+d x)}{b^2 d}+\frac {\tan ^2(c+d x)}{2 b d} \]
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Rule 711
Rule 3587
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1+\frac {x^2}{b^2}}{a+x} \, dx,x,b \tan (c+d x)\right )}{b d} \\ & = \frac {\text {Subst}\left (\int \left (-\frac {a}{b^2}+\frac {x}{b^2}+\frac {a^2+b^2}{b^2 (a+x)}\right ) \, dx,x,b \tan (c+d x)\right )}{b d} \\ & = \frac {\left (a^2+b^2\right ) \log (a+b \tan (c+d x))}{b^3 d}-\frac {a \tan (c+d x)}{b^2 d}+\frac {\tan ^2(c+d x)}{2 b d} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.88 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\left (a^2+b^2\right ) \log (a+b \tan (c+d x))-a b \tan (c+d x)+\frac {1}{2} b^2 \tan ^2(c+d x)}{b^3 d} \]
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Time = 7.50 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.90
method | result | size |
derivativedivides | \(\frac {-\frac {-\frac {b \left (\tan ^{2}\left (d x +c \right )\right )}{2}+a \tan \left (d x +c \right )}{b^{2}}+\frac {\left (a^{2}+b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3}}}{d}\) | \(53\) |
default | \(\frac {-\frac {-\frac {b \left (\tan ^{2}\left (d x +c \right )\right )}{2}+a \tan \left (d x +c \right )}{b^{2}}+\frac {\left (a^{2}+b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3}}}{d}\) | \(53\) |
risch | \(\frac {-2 i a \,{\mathrm e}^{2 i \left (d x +c \right )}+2 b \,{\mathrm e}^{2 i \left (d x +c \right )}-2 i a}{b^{2} d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) a^{2}}{b^{3} d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{b d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) a^{2}}{b^{3} d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right )}{b d}\) | \(170\) |
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Leaf count of result is larger than twice the leaf count of optimal. 117 vs. \(2 (57) = 114\).
Time = 0.26 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.98 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {{\left (a^{2} + b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}\right ) - {\left (a^{2} + b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (\cos \left (d x + c\right )^{2}\right ) - 2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b^{2}}{2 \, b^{3} d \cos \left (d x + c\right )^{2}} \]
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\[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\int \frac {\sec ^{4}{\left (c + d x \right )}}{a + b \tan {\left (c + d x \right )}}\, dx \]
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Time = 0.62 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.90 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\frac {b \tan \left (d x + c\right )^{2} - 2 \, a \tan \left (d x + c\right )}{b^{2}} + \frac {2 \, {\left (a^{2} + b^{2}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{b^{3}}}{2 \, d} \]
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Time = 0.38 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.92 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\frac {b \tan \left (d x + c\right )^{2} - 2 \, a \tan \left (d x + c\right )}{b^{2}} + \frac {2 \, {\left (a^{2} + b^{2}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{b^{3}}}{2 \, d} \]
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Time = 4.05 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.97 \[ \int \frac {\sec ^4(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {{\mathrm {tan}\left (c+d\,x\right )}^2}{2\,b\,d}+\frac {\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )\,\left (a^2+b^2\right )}{b^3\,d}-\frac {a\,\mathrm {tan}\left (c+d\,x\right )}{b^2\,d} \]
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